Definite Integration

On this placeholder page we present the essentials of definite integration, including how to use the power rule, exponential rule, and trigonometric rules. Of course we have typical problems below, each with a complete solution immediately available, so you can see how they are used routinely, including in some typical exam questions. Let's jump right in!

Here are the main rules you'll need. We have illustration of each problem type below.

MATHENO ESSENTIALS: Definite Integration

Important Notation

When we write [๐น(๐‘ฅ)]๐‘๐‘Ž, it means ๐น(๐‘) minus ๐น(๐‘Ž):

[๐น(๐‘ฅ)]๐‘๐‘Ž=๐น(๐‘)โˆ’๐น(๐‘Ž)

Power Rule: Integration of ๐‘ฅ๐‘› (๐‘› โ‰  โˆ’1)

If you're integrating x-to-some-power (except ๐‘ฅโˆ’1), the rule to remember is: "Increase the power by 1, and then divide by the new power." We can express this process mathematically asโˆซ๐‘๐‘Ž๐‘ฅ๐‘›๐‘‘๐‘ฅ=1๐‘›+1[๐‘ฅ๐‘›+1]๐‘๐‘Ž(๐‘›โ‰ โˆ’1)=1๐‘›+1[๐‘๐‘›+1โˆ’๐‘Ž๐‘›+1]

Exponential Rule: Integration of ๐‘’๐‘ฅ

This integral is the easiest to remember: since (๐‘’๐‘ฅ)โ€ฒ =๐‘’๐‘ฅ, the integral of ๐‘’๐‘ฅ is also ๐‘’๐‘ฅโˆซ๐‘๐‘Ž๐‘’๐‘ฅ๐‘‘๐‘ฅ=[๐‘’๐‘ฅ]๐‘๐‘Ž=๐‘’๐‘โˆ’๐‘’๐‘Ž

Exponential Rule: Integration of ๐‘๐‘ฅ (where ๐‘ is a constant)

โˆซ๐‘๐‘Ž๐‘๐‘ฅ=1lnโก๐‘[๐‘๐‘ฅ]๐‘๐‘Ž=1lnโก๐‘[๐‘๐‘โˆ’๐‘๐‘Ž]

Trigonometric Rules: Integrals of Trig Functions

โˆซ๐‘๐‘Žcosโก๐‘ฅ๐‘‘๐‘ฅ=[sinโก๐‘ฅ]๐‘๐‘Žโˆซ๐‘๐‘Žsinโก๐‘ฅ๐‘‘๐‘ฅ=โˆ’[cosโก๐‘ฅ]๐‘๐‘Žโˆซ๐‘๐‘Žsec2โก๐‘ฅ๐‘‘๐‘ฅ=[tanโก๐‘ฅ]๐‘๐‘Žโˆซ๐‘๐‘Žsecโก๐‘ฅtanโก๐‘ฅ๐‘‘๐‘ฅ=[secโก๐‘ฅ]๐‘๐‘Žโˆซ๐‘๐‘Žcsc2โก๐‘ฅ๐‘‘๐‘ฅ=โˆ’[cotโก๐‘ฅ]๐‘๐‘Ž

You might also be expected to know the integrals for sin2โก๐‘ฅ and cos2โก๐‘ฅ, because they follow immediately from use of the half-angle formulas:

โˆซ๐‘๐‘Žsin2โก๐‘ฅ๐‘‘๐‘ฅ=โˆซ๐‘๐‘Ž(12โˆ’12cosโก2๐‘ฅ)๐‘‘๐‘ฅ=[12๐‘ฅโˆ’14sinโก2๐‘ฅ]๐‘๐‘Žโˆซ๐‘๐‘Žcos2โก๐‘ฅ๐‘‘๐‘ฅ=โˆซ๐‘๐‘Ž(12+12cosโก2๐‘ฅ)๐‘‘๐‘ฅ=[12๐‘ฅ+14sinโก2๐‘ฅ]๐‘๐‘Ž

You can practice each of these common integration problems below.

I. Power Rule

If you're integrating x-to-some-power (except ๐‘ฅโˆ’1), the rule to remember is:

"Increase the power by 1, and then divide by the new power."

We can express this process mathematically as

โˆซ๐‘๐‘Ž๐‘ฅ๐‘›๐‘‘๐‘ฅ=1๐‘›+1[๐‘ฅ๐‘›+1]๐‘๐‘Ž(๐‘›โ‰ โˆ’1)=1๐‘›+1[๐‘๐‘›+1โˆ’๐‘Ž๐‘›+1]
For example
Power Rule Practice Problem #1
(a)
Evaluate the integral: โˆซ517๐‘‘๐‘ฅ.
(b)
Evaluate the integral: โˆซ51๐‘ฅ๐‘‘๐‘ฅ.
(c)
Evaluate the integral: โˆซ51(7+๐‘ฅ)๐‘‘๐‘ฅ.
Power Rule Practice Problem #2
(a)
Evaluate the integral: โˆซ20๐‘ฅ2๐‘‘๐‘ฅ.
(b)
Evaluate the integral: โˆซ205๐‘ฅ4๐‘‘๐‘ฅ.
(c)
Evaluate the integral: โˆซ20(๐‘ฅ2โˆ’5๐‘ฅ4)๐‘‘๐‘ฅ.
Power Rule Practice Problem #3
Evaluate the integral: โˆซ0โˆ’3(23๐‘ค5โˆ’14๐‘ค3+๐‘ค)๐‘‘๐‘ค.
Power Rule Practice Problem #4
Evaluate the integral: โˆซ05(๐‘ฅ2โˆ’1)2๐‘‘๐‘ฅ.
Power Rule Practice Problem #5
Evaluate the integral: โˆซ214๐‘ฅโˆ’7๐‘ฅ5๐‘ฅ3๐‘‘๐‘ฅ.
Power Rule Practice Problem #6
(a)
Evaluate the integral: โˆซ91โˆš๐‘ฅ๐‘‘๐‘ฅ.
(b)
Evaluate the integral: โˆซ911โˆš๐‘ฅ๐‘‘๐‘ฅ.
(c)
Evaluate the integral: โˆซ91(โˆš๐‘ฅโˆ’1โˆš๐‘ฅ)๐‘‘๐‘ฅ.
Power Rule Practice Problem #7
Evaluate the integral: โˆซ94๐‘ฅโˆ’5โˆš๐‘ฅ๐‘‘๐‘ฅ.
Power Rule Practice Problem #8
Evaluate the integral: โˆซ10(5โˆš๐‘ฅ5+23โˆš๐‘ฅ2)๐‘‘๐‘ฅ.

II. Exponential, ๐‘’๐‘ฅ

This integral is the easiest to remember: since (๐‘’๐‘ฅ)โ€ฒ =๐‘’๐‘ฅ, the integral of ๐‘’๐‘ฅ is also ๐‘’๐‘ฅ :

โˆซ๐‘๐‘Ž๐‘’๐‘ฅ๐‘‘๐‘ฅ=[๐‘’๐‘ฅ]๐‘๐‘Ž=๐‘’๐‘โˆ’๐‘’๐‘Ž
Exponential Rule ๐‘’๐‘ฅ Practice Problem #1
Evaluate the integral: โˆซ315๐‘’๐‘ฅ๐‘‘๐‘ฅ.
Exponential Rule ๐‘’๐‘ฅ Practice Problem #2
Evaluate the integral: โˆซ41(1โˆš๐‘ฅ5โˆ’๐‘’๐‘ฅ)๐‘‘๐‘ฅ.

III. Exponential, ๐‘๐‘ฅ (where ๐‘ is a constant)

Here ๐‘ is a constant (a number, any number). Then

โˆซ๐‘๐‘Ž๐‘๐‘ฅ=1lnโก๐‘[๐‘๐‘ฅ]๐‘๐‘Ž=1lnโก๐‘[๐‘๐‘โˆ’๐‘๐‘Ž]
Exponential Rule ๐‘๐‘ฅ Practice Problem #1
Evaluate the integral: โˆซ203๐‘ฅ๐‘‘๐‘ฅ.
Exponential Rule ๐‘๐‘ฅ Practice Problem #2
Evaluate the integral: โˆซ10(๐‘ฅ5+5๐‘ฅ)๐‘‘๐‘ฅ.

IV. Trig Functions

We're listing here only the trig integrals that you should be familiar with at this early stage: each of these follows directly from a derivative you immediately know. For example, since
(sinโก๐‘ฅ)โ€ฒ=cosโก๐‘ฅ
we know immediately that
โˆซ๐‘๐‘Žcosโก๐‘ฅ๐‘‘๐‘ฅ=[sinโก๐‘ฅ]๐‘๐‘Ž
Accordingly:

โˆซ๐‘๐‘Žcosโก๐‘ฅ๐‘‘๐‘ฅ=[sinโก๐‘ฅ]๐‘๐‘Žโˆซ๐‘๐‘Žsinโก๐‘ฅ๐‘‘๐‘ฅ=โˆ’[cosโก๐‘ฅ]๐‘๐‘Žโˆซ๐‘๐‘Žsec2โก๐‘ฅ๐‘‘๐‘ฅ=[tanโก๐‘ฅ]๐‘๐‘Žโˆซ๐‘๐‘Žsecโก๐‘ฅtanโก๐‘ฅ๐‘‘๐‘ฅ=[secโก๐‘ฅ]๐‘๐‘Žโˆซ๐‘๐‘Žcsc2โก๐‘ฅ๐‘‘๐‘ฅ=โˆ’[cotโก๐‘ฅ]๐‘๐‘Ž
Each integral follows directly from a derivative you know. You can review those using our Trig Function Derivatives table; it's always available from the Reference menu at the top of every page.


You might also be expected to know the integrals for sin2โก๐‘ฅ and cos2โก๐‘ฅ, because they follow immediately from use of the half-angle formulas:

sin2โก๐‘ฅ=12โˆ’12cosโก2๐‘ฅcos2โก๐‘ฅ=12+12cosโก2๐‘ฅ

Then

โˆซ๐‘๐‘Žsin2โก๐‘ฅ๐‘‘๐‘ฅ=โˆซ(12โˆ’12cosโก2๐‘ฅ)๐‘‘๐‘ฅ=[12๐‘ฅโˆ’14sinโก2๐‘ฅ]๐‘๐‘Žโˆซ๐‘๐‘Žcos2โก๐‘ฅ๐‘‘๐‘ฅ=โˆซ(12+12cosโก2๐‘ฅ)๐‘‘๐‘ฅ=[12๐‘ฅ+14sinโก2๐‘ฅ]๐‘๐‘Ž
Trig Function Practice Problem #1
Evaluate the integral: โˆซ๐œ‹/204cosโก๐‘ฅ๐‘‘๐‘ฅ.
Trig Function Practice Problem #2
Evaluate the integral: โˆซ๐œ‹012sinโก๐œƒ๐‘‘๐œƒ.
Trig Function Practice Problem #3
Evaluate the integral: โˆซ๐œ‹/40๐‘‘๐‘ฅsecโก๐‘ฅ.
Trig Function Practice Problem #4
Evaluate the integral: โˆซ๐œ‹/40sec2โก๐‘ฅ๐‘‘๐‘ฅ.
Trig Function Practice Problem #5
Evaluate the integral: โˆซ๐œ‹/3๐œ‹/6secโก๐‘ฅtanโก๐‘ฅ๐‘‘๐‘ฅ.
Trig Function Practice Problem #6
Evaluate the integral: โˆซ3๐œ‹/4๐œ‹/4(csc2โก๐‘ฅ+2๐‘ฅ2)๐‘‘๐‘ฅ.
Trig Function Practice Problem #7
Evaluate the integral: โˆซ๐œ‹/303+2cos2โก๐‘ฅcos2โก๐‘ฅ๐‘‘๐‘ฅ.

You may also be expected to use the Trig Identity and its variants:

sin2โก๐‘ฅ+cos2โก๐‘ฅ=11+cot2โก๐‘ฅ=csc2โก๐‘ฅ1+tan2โก๐‘ฅ=sec2โก๐‘ฅ

We'll of course illustrate the use of these identities in the problems below.

Trig Function Practice Problem #8
Evaluate the integral: โˆซ๐œ‹/40tan2โก๐‘ฅ๐‘‘๐‘ฅ.
Trig Function Practice Problem #9
Evaluate the integral: โˆซ๐œ‹/405sinโก๐‘ฅ+5sinโก๐‘ฅtan2โก๐‘ฅsec2โก๐‘ฅ๐‘‘๐‘ฅ.
Trig Function Practice Problem #10
Evaluate the integral: โˆซ๐œ‹/3๐œ‹/6sec3โก๐‘ฅโˆ’secโก๐‘ฅtanโก๐‘ฅ๐‘‘๐‘ฅ.

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