## Related Rates

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Justas
3 months ago

That’s a wonderful explanation, but I’m having a bit of a problem understanding the 3d step. As an eastern European – we use the f'(x) notation more often, so I blatantly just don’t understand the example :D.
Could u give a solution based on v(t)=s'(t) and a(t)=v'(t)?
I also don’t really get the “in respect to time” part…

Last edited 3 months ago by Justas
Bruce
Editor
3 months ago

Thank you for your question! We now use our Forum for such questions and answers since it offers a LOT more functionality than the ‘comments’ here.

Emily Dulpina
2 years ago

Shan, who is 2 meters tall, is approaching a post that holds a lamp 6 meters above the ground. If he is walking at a speed of 1:5 m/s, how fast is the end of his shadow moving (with respect to the lamp post) when he is 6 meters away from the base of the lamp post?

Can you help me on how to solve this?

Marissa
4 years ago

how did you get .70l=x, from l-.30l=x

Nicky G
4 years ago

Hi there, when you find the relationship between L and x, why do you put the L-x and 1.8 on top of the cross multiplication problem? Is that like a rule or something that the smaller triangle components go on top?

Nikhith Pagidi
4 years ago

Rate of increase of distance between man’s head and tip of shadow ( head )? In the above problem

Nikhith Pagidi
4 years ago

No ,I think Mr matheno you didn’t get my question
The answer you have given is correct for rate of increase of shadow of a person

Nikhith Pagidi
4 years ago

Mr matheno
Let man be AB ( A is on ground and B is head)
And pole of lamp be OP(O is on ground and P be tip of lamp)

Now my question is that ,
Rate of increase of BB’?

Nikhith Pagidi
4 years ago

Hmm… I too did the same
But getting a lengthy process