## Related Rates

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Anonymous
5 months ago

when you turn the equation of the volume of a cone into rate in terms of time why wouldn’t v= turn into V(dv/dt).

Anonymous
6 months ago

I would like to ask, what if the rate is not constant. What if when the depth of the water was 6ft, the water surface is changing at a rate of 15cm3/s? And the water drained completely

Anonymous
8 months ago

-15/16Pi cubic cm? not just cm in the answer?

Julián Sierra
1 year ago

The statement says: NOW the flow rate is 15cm3 in present.
Then what is the height loss rate WHEN THE HEIGHT IS HALFWAY 10cm, it sounds like it will be 10 cm in the future, which could lead to a misunderstanding. It would help to state that it is the same moment, “now the height is halfway 10cm”

Erin K
5 years ago

What if you don’t have a value for dV/dt? I have a problem where I am given the height of the water, but not given any values for the speed at which it’s draining.

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